IB Chemistry HL Topic 6 — Electron Transfer Paper 1 & 2 Organic ~8 min read

Reducing Unsaturated Compounds

Adding hydrogen across a double or triple bond is called hydrogenation, and it is a reduction. It is also the reaction that turns runny vegetable oil into margarine you can spread — one of the few bits of organic chemistry sitting in most people’s fridges.

📚 What you need to know

One hydrogen molecule per multiple bond

Down the ladder, one H₂ at a time Each multiple bond swallows one molecule of hydrogen alkyne triple bond C≡C alkene double bond C=C alkane single bond C—C +H₂ +H₂ Ni catalyst Ni catalyst Typical conditions: nickel catalyst, about 200 °C, 1000 kPa Platinum and palladium work at lower temperatures but cost far moreAn alkyne needs two, an alkene needs one The product is saturated: every carbon holds as much hydrogen as it can.
Count the multiple bonds and you have counted the moles of hydrogen. That single idea answers almost every calculation on this topic.
Ethene to ethane CH2=CH2 + H2 → CH3CH3
Ethyne all the way to ethane CH≡CH + 2H2 → CH3CH3
Why is this a reduction when nothing obviously loses electrons? Check the oxidation numbers on the carbons. In ethene each carbon is −2; in ethane each is −3. The number falls, so the carbons have been reduced. The old rule “reduction is gain of hydrogen” is really just this in disguise.

From oil to margarine

Vegetable oils are unsaturated: their long fatty acid chains contain C=C double bonds. Those double bonds put permanent kinks in the chains, so the molecules cannot pack together neatly. Weak packing means weak London forces, a low melting point, and an oil that is liquid at room temperature.

Hydrogenate some of those double bonds and the chains straighten out:

Why only partly hydrogenate? Fully saturating the oil gives something hard and waxy that will not spread. Manufacturers stop part way, leaving some C=C bonds behind, to land on a texture that is solid in the fridge but soft enough to use straight away.
There is a real trade-off here worth knowing for an evaluation question. Partial hydrogenation can convert some natural cis double bonds into trans ones, and trans fats are linked to heart disease. Many manufacturers now use other methods for exactly this reason.

Worked examples

WORKED EXAMPLE

0.200 mol of an oil molecule containing three C=C bonds is fully hydrogenated. Calculate the volume of hydrogen needed at STP. (Molar volume = 22.7 dm3 mol−1)

Step 1: One H2 per double bond Three double bonds per molecule means three H2 per molecule. n(H2) = 0.200 × 3 = 0.600 mol Step 2: Convert moles to volume V = 0.600 × 22.7 = 13.62 dm3 13.6 dm3 of hydrogen “fully” is the key word — it means every multiple bond reacts
WORKED EXAMPLE

But-2-yne is reacted with one mole equivalent of hydrogen over a nickel catalyst. Give the product and its molecular formula.

Step 1: Start from the alkyne But-2-yne is C4H6, with a triple bond between carbons 2 and 3. Step 2: One H2 takes the triple bond down to a double bond C4H6 + H2 → C4H8 Step 3: Name it The double bond is still between carbons 2 and 3. But-2-ene, C4H8 a second mole of H2 would take it on to butane, C4H10
WORKED EXAMPLE

Explain, in terms of intermolecular forces, why a hydrogenated vegetable oil is solid at room temperature while the original oil is liquid.

Step 1: Describe the unsaturated molecules C=C bonds put kinks in the chains, so the molecules cannot pack closely. Step 2: Link packing to the forces Less surface contact means weaker London dispersion forces between molecules. Step 3: Describe the saturated product Removing the C=C bonds straightens the chains, so they pack closer, contact more and attract more strongly. Stronger London forces need more energy to overcome, so the melting point rises the chain of reasoning is shape, then packing, then forces, then melting point

💡 Exam tip

⚠ Common mix-up

Up next: The Hydrogen Electrode — back to electrochemistry for the HL material, starting with the reference point that gives every half-cell its number.

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