IB Chemistry SL Topic 4 — Energy from Fuels Paper 1 & 2 Core skill ~13 min read

Carbon Dioxide from Burning Fuels

Every carbon atom in a fuel leaves as a molecule of carbon dioxide. That makes the emissions of a fuel something you can calculate exactly, from nothing more than its formula and a balanced equation.

📚 What you need to know

Fossil fuels

Coal, oil and natural gas are all mixtures of hydrocarbons, formed over millions of years from the remains of dead organisms buried in the Earth’s crust. They are non-renewable: they are being consumed vastly faster than geology replaces them, so the supply is finite.

FuelIn its favourAgainst it
CoalCheap, abundant, safe to store, long-lasting reservesMost CO2 per joule; sulfur impurities give SO2 and acid rain; particulates; mining damages habitats and endangers miners
OilHigh energy density, easy to transport by pipeline or tanker, separable by fractional distillation into useful fractionsCO2, SO2 and CO on burning; spills damage ecosystems; unevenly distributed geographically
Natural gasHighest specific energy, cleanest burning, little sulfur so no significant acid rainStill releases CO2; low energy density means pressurised storage; leaks release methane, itself a potent greenhouse gas

Specific energy

Specific energy the energy released per unit mass of fuel, in kJ g–1 or MJ kg–1

Specific energy is simply the enthalpy of combustion divided by the molar mass, which makes it a one-line calculation from data you already have. Keep it separate from energy density, which is energy per unit volume — the distinction matters for hydrogen, which is superb per kilogram and hopeless per litre.

Aircraft care about specific energy, because every kilogram has to be lifted. Car boots and gas cylinders care about energy density, because space is what runs out first. A question that mentions tank size is asking about the second one.

The trend along the alkanes

GOING UP THE ALKANE SERIESper gram of fuel burnt2.73.1465612345678number of carbon atoms in the alkanemass of CO₂ per gram / genergy per gram / kJ g−¹longer chains: more carbon dioxide, less energy, for every gram burnt
Both curves flatten out, because as the chain gets longer, adding one more CH2 changes the overall carbon-to-hydrogen ratio less and less.

The chemistry behind both curves is the same single fact: burning hydrogen releases more energy per gram than burning carbon does. So a fuel’s hydrogen-to-carbon ratio decides everything.

Two further consequences of longer chains are worth knowing: stronger London dispersion forces make them less volatile and harder to vaporise, and their higher carbon content makes incomplete combustion more likely.

Calculating the carbon dioxide

🧩 The method, every time

  1. Write and balance the equation for complete combustion.
  2. Find moles of fuel from n = mass ÷ Mr.
  3. Moles of CO2 = moles of fuel × number of carbons, straight from the equation.
  4. Convert back: mass = moles × 44.01.
  5. If you are comparing fuels, divide by the energy released, not by the mass.
WORKED EXAMPLE

Calculate the mass of carbon dioxide produced when 1.00 g of propane, C3H8, burns completely. (Mr: C3H8 = 44.11, CO2 = 44.01)

Step 1 — the equation C₃H₈ + 5O₂ → 3CO₂ + 4H₂O Step 2 — moles of propane n = 1.00 ÷ 44.11 = 0.02267 mol Step 3 — moles of CO₂ 0.02267 × 3 = 0.06801 mol Step 4 — mass 0.06801 × 44.01 = 2.993 mass of CO₂ = 2.99 g Three times the mass of fuel you started with. The extra mass is oxygen taken from the air.
WORKED EXAMPLE

Compare the CO2 released per gram by methane (Mr = 16.05) and octane (Mr = 114.26) burning completely.

Methane, 1 carbon n = 1.00 ÷ 16.05 = 0.0623 mol → 0.0623 mol CO₂ 0.0623 × 44.01 = 2.74 g Octane, 8 carbons n = 1.00 ÷ 114.26 = 0.00875 mol → × 8 = 0.0700 mol CO₂ 0.0700 × 44.01 = 3.08 g 2.74 g vs 3.08 g per gram of fuel A 12% difference — real, but smaller than most people expect. The bigger gap appears once you allow for the energy each one gives.

Comparing fuels fairly

Per gram is the wrong comparison, because nobody buys a fuel by the gram — they buy it to deliver a certain amount of energy. Divide the CO2 by the energy released and the honest comparison appears.

CARBON DIOXIDE FOR THE SAME ENERGYgrams of CO₂ released per megajoule of energy49methanenatural gas64octanepetrol112carboncoal, idealisedburning methane emits less than half the CO₂ of burning carbon
The same job done three ways. This is the calculation behind every claim that natural gas is a “cleaner” fossil fuel.
WORKED EXAMPLE

Methane has a specific energy of 55.5 kJ g–1 and octane 47.9 kJ g–1. Using the masses of CO2 per gram from the previous example, compare the CO2 released per megajoule.

Methane 2.74 ÷ 55.5 = 0.0494 g per kJ → 49 g per MJ Octane 3.08 ÷ 47.9 = 0.0643 g per kJ → 64 g per MJ methane emits about 30% less CO₂ per MJ Per gram the gap was 12%; per unit of useful energy it is nearly a third. Methane wins twice over — less carbon to start with, and more energy from each gram.

💡 Exam tip

⚠️ Common mix-up

Up next: CO2 Levels and the Greenhouse Effect — where all that carbon dioxide ends up, and the reason a molecule of it warms the planet while a molecule of nitrogen does not.

Want this explained one-to-one?

Book a free session with an experienced IB Chemistry tutor and get your trickiest topics made simple.

Book a Free Session →