IB Chemistry SL Topic 4 — Energy from Fuels Paper 1 & 2 Core idea ~12 min read

Combustion Reactions

Burning is the reaction civilisation runs on, and chemically it is nothing more than oxidation happening fast enough to glow. What comes out the other end depends entirely on what went in — and on how much oxygen was available.

📚 What you need to know

What combustion actually is

Combustion a rapid, exothermic reaction between a fuel and oxygen, releasing heat and light

Every part of that definition earns its place. Exothermic, because the bonds formed in the oxides are stronger than the bonds broken in the fuel. Rapid, because slow oxidation — iron rusting, for instance — releases exactly the same energy without ever producing a flame. And light, because the reaction gets hot enough for the products to glow.

THE THREE THINGS A FIRE NEEDScombustion is a reaction, not a substanceFUELsomething that can be oxidisedOXYGENusually from the airHEATa spark or a flameCOMBUSTIONrapid, exothermictake away any one corner and the flame goes out
Fuel, oxygen, heat. Every method of putting out a fire works by removing one of the three.
Fuels do not burst into flame on the shelf even though the reaction is strongly exothermic. That is because combustion has a high activation energy — a spark is needed to start it. Handy for anyone who stores petrol.

Burning metals

All metals can be oxidised, but not all of them combust, which means burning with a flame. Two things decide it:

The standard example is magnesium, which burns with a fierce white light:

A metal burning 2Mg(s) + O2(g) → 2MgO(s)
metal + oxygen → metal oxide

Metal oxides are ionic, and those that dissolve give alkaline solutions — they are basic oxides. Magnesium oxide in water gives a pH comfortably above 7.

A few metals are awkward: sodium burnt in plenty of oxygen gives the peroxide Na2O2, and iron gives Fe3O4. This is beyond what you are examined on — write the ordinary oxides, Na2O and Fe2O3, and you will be given the marks.

Burning non-metals

Non-metals burn too, and the products behave in the opposite way. Sulfur burns with a blue flame:

A non-metal burning S(s) + O2(g) → SO2(g)
non-metal + oxygen → non-metal oxide

These oxides are covalent and molecular, and they dissolve to give acids — sulfur dioxide is the origin of acid rain. So the two halves of the periodic table give you two opposite kinds of oxide, and that is a favourite one-mark question.

WHAT THE OXIDE DOES IN WATERwhich side of the periodic table the element came fromACIDICBASICpH 0pH 7pH 14NON-METAL OXIDESSO₂  CO₂  P₄O₁₀METAL OXIDESNa₂O  MgO  CaOcovalent, molecularionic, giant latticemetals burn to basic oxides, non-metals burn to acidic oxides
Which side of the table the element came from tells you what its oxide will do in water.

Complete combustion of organic fuels

Hydrocarbons and alcohols are the fuels that matter commercially, and burnt in excess oxygen they undergo complete combustion: every carbon ends up fully oxidised to carbon dioxide, and every hydrogen ends up as water.

Complete combustion fuel + oxygen → carbon dioxide + water

Nothing else appears. If you have written anything other than CO2 and H2O on the right-hand side, either the equation is wrong or the combustion was not complete.

BALANCE IN THIS ORDER1CARBONone CO₂ per C2HYDROGENone H₂O per 2 H3OXYGENcount both productsIF THE FUEL IS AN ALCOHOLit already contains oxygen — subtract it before you set the O₂ coefficientoxygen last, always — it is the only element in a molecule of its own
Oxygen goes last because it is the only element that appears in a molecule on its own, so it can absorb whatever number is left over.

🧩 Balancing a combustion equation

  1. Write the products as CO2 and H2O.
  2. Carbon: the number of C atoms in the fuel is the coefficient of CO2.
  3. Hydrogen: half the number of H atoms in the fuel is the coefficient of H2O.
  4. Oxygen: count all the O atoms in the products, subtract any oxygen already in the fuel, then halve what is left to get the O2 coefficient.
  5. A half is allowed. Double everything if the question insists on whole numbers.
WORKED EXAMPLE

Write balanced equations for (a) aluminium burning to aluminium oxide, Al2O3, and (b) lithium burning to lithium oxide, Li2O.

(a) start from the formula of the product Al + O₂ → Al₂O₃ Three O on the right, two on the left. Take 2 Al₂O₃ to make six O, which needs 3 O₂. 4Al(s) + 3O₂(g) → 2Al₂O₃(s) (b) same routine Li₂O has one O, so two of them use up one O₂, needing 4 Li. 4Li(s) + O₂(g) → 2Li₂O(s) The oxide formula comes from the charges: Al³⁺ with O²− gives Al₂O₃, Li⁺ with O²− gives Li₂O.
WORKED EXAMPLE

Write the equation for the complete combustion of butane, C4H10.

Step 1 — carbon 4 C → 4CO₂ Step 2 — hydrogen 10 H → 5H₂O Step 3 — oxygen last (4 × 2) + 5 = 13 O atoms → 6½ O₂ C₄H₁₀ + 6½O₂ → 4CO₂ + 5H₂O Doubling gives whole numbers: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O. Keep the half if the question asks for one mole of fuel.
WORKED EXAMPLE

Write the equation for the complete combustion of methanol, CH3OH.

Steps 1 and 2 — carbon and hydrogen 1 C → CO₂    4 H → 2H₂O Step 3 — oxygen, minus what the fuel brought Products contain 2 + 2 = 4 O atoms. Methanol already supplies 1. 4 − 1 = 3 → 3 ÷ 2 = 1½ O₂ CH₃OH + 1½O₂ → CO₂ + 2H₂O Forgetting the oxygen inside the alcohol gives 2O₂ and an unbalanced equation. It is the single most common slip here.

💡 Exam tip

⚠️ Common mix-up

Up next: Incomplete Combustion — what happens when the oxygen runs short, why the flame turns yellow, and why a faulty boiler can kill you.

Want this explained one-to-one?

Book a free session with an experienced IB Chemistry tutor and get your trickiest topics made simple.

Book a Free Session →