IB Chemistry SL Topic 2 — Ionic Bonding Paper 1 & 2 Core idea ~9 min read

Forming Ions

Atoms are neutral. Ions are not. The whole of ionic bonding starts with one simple event — electrons moving from a metal atom to a non-metal atom — and once you can predict how many move, you can predict almost every ionic formula in the course.

📚 What you need to know

Why atoms form ions

Metals sit on the left of the periodic table and have few outer electrons. Non-metals sit on the right and are only a few electrons short of a full shell. When they meet, the cheapest route to a full outer shell for both is a straight transfer:

Sodium and chlorine are the classic pair. Sodium has one outer electron it can shed; chlorine has seven and needs exactly one more.

SODIUM ATOM Na [2,8,1] Na 1 outer electron LOSES 1 e⁻ SODIUM ION Na⁺ [2,8] + Na full outer shell, same as Ne CHLORINE ATOM Cl [2,8,7] Cl 7 outer electrons — needs 1 GAINS 1 e⁻ CHLORIDE ION Cl⁻ [2,8,8] Cl gained electron shown in red
The transferred electron (red) leaves sodium positive and chlorine negative. Neither has changed element — only the electron count has changed.
Once formed, Na⁺ has the electron arrangement [2,8] — identical to neon. Cl⁻ has [2,8,8] — identical to argon. That’s the pattern examiners want you to spot: ions are isoelectronic with the nearest noble gas.

Predicting the charge from the group

You don’t need to memorise every ion. The group number tells you how many electrons an atom has to lose or gain to reach a full shell:

GROUP 12131415161718 Li⁺ Be²⁺ N³⁻ O²⁻ F⁻ NONE Na⁺ Mg²⁺ Al³⁺ P³⁻ S²⁻ Cl⁻ NONE K⁺ Ca²⁺ Ga³⁺ Br⁻ NONE Rb⁺ Sr²⁺ I⁻ NONE TRANSITION ELEMENTS blue = cations (metals lose electrons)  •  red = anions (non-metals gain electrons)
The charge of a simple ion follows directly from its position in the periodic table.

🧩 The 10-second method

  1. Metal or non-metal? Metal → positive. Non-metal → negative.
  2. Find the group. Groups 1, 2, 13 → charge = +1, +2, +3.
  3. Groups 15, 16, 17 → charge = group number − 18, so −3, −2, −1.
  4. Group 18 already has a full shell → forms no ions.
WORKED EXAMPLE

Deduce the formula of the ion formed by (a) barium, (b) selenium, (c) aluminium.

(a) Ba — metal, group 2, loses 2 electrons Ba²⁺ (b) Se — non-metal, group 16, gains 2 electrons Se²⁻ (c) Al — metal, group 13, loses 3 electrons Al³⁺
WORKED EXAMPLE

A sulfur atom has the electron arrangement [2,8,6]. Deduce the arrangement of the sulfide ion and identify the noble gas it matches.

Sulfur is group 16, so it gains 2 electrons 6 + 2 = 8 electrons in the outer shell. S²⁻ = [2,8,8] — 16 protons, 18 electrons Same arrangement as argon Careful: it is not argon — the proton number is still 16.

Transition elements: variable charges

Transition elements break the tidy pattern — the same metal can form more than one ion. Iron, for example, forms both Fe2+ and Fe3+. Because the group number can no longer tell you the charge, the name has to:

Read it backwards too: if a question gives you the formula CuO, you know oxygen is O2−, so copper must be Cu2+ — the compound is copper(II) oxide.

Polyatomic ions

Not every ion is a single atom. Polyatomic ions are groups of covalently bonded atoms carrying an overall charge, and they behave as one unit in ionic compounds. Seven of them appear in the IB data booklet — learn them as a block:

IonFormula & chargeIonFormula & charge
AmmoniumNH4+CarbonateCO32−
HydroxideOHSulfateSO42−
NitrateNO3PhosphatePO43−
HydrogencarbonateHCO3

Ammonium is the odd one out — it is the only positive polyatomic ion on the list, and it lets a compound be ionic with no metal in it at all (ammonium chloride, NH4Cl).

💡 Exam tip

⚠️ Common mix-up

Up next: Binary Ionic Compounds — how to combine the ions you can now predict into correct formulae, and how to name them the IUPAC way.

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