IB Chemistry SL Topic 4 — Energy from Fuels Paper 1 & 2 Core idea ~12 min read

Incomplete Combustion

Restrict the oxygen and the carbon in a fuel cannot be fully oxidised. What comes out instead is carbon monoxide, or soot, or both — less energy, more mess, and a gas that kills people in their sleep.

📚 What you need to know

What limited oxygen does

Complete combustion oxidises every carbon atom all the way to CO2. That takes a lot of oxygen. Supply less, and the carbon only makes it part of the way — first to carbon monoxide, and if the supply is very poor, not at all, leaving elemental carbon.

HOW MUCH OXYGEN DECIDES THE PRODUCTless O₂plenty of oxygenCO₂ + H₂Ocompletelimited oxygenCO + H₂Oincompletevery little oxygenC (soot) + H₂Oincompletewater every time — hydrogen is oxidised in preference to carbon
One fuel, three possible outcomes. In a real flame you usually get a mixture of all three.

Notice what does not change: water appears in every row. Hydrogen is oxidised preferentially, so however starved of oxygen a flame is, it never releases hydrogen gas. If you have written H2 as a product, something has gone wrong.

There is an energy consequence too. Carbon monoxide still has an unburnt bond’s worth of energy left in it — that is why it is itself a fuel. So incomplete combustion always releases less energy per mole of fuel than complete combustion, which is why a badly adjusted burner is wasteful as well as dangerous.

Reading the flame

THE FLAME TELLS YOUsame burner, same gas, different air supplyAIR HOLE CLOSEDyellow, luminous, sootyincomplete combustionAIR HOLE OPENblue, non-luminous, hottercomplete combustiona yellow, sooty flame is unburnt carbon glowing
The yellow glow is not the gas. It is solid carbon particles heated until they radiate light — the same effect as a candle.

A Bunsen burner is a controlled demonstration of the whole idea. Close the air hole and the gas mixes with air only at the flame edge, so combustion is incomplete: the flame is yellow, luminous, wavy and relatively cool, and it deposits soot on anything held in it. Open the air hole and the gas premixes with air before it burns: the flame becomes blue, non-luminous and much hotter, with a clear inner cone.

This is why calorimetry with a spirit burner comes out badly. Soot on the bottom of the can is unburnt carbon — energy that was never released at all, which is exactly why measured enthalpies of combustion come out less exothermic than the data booklet value.

Writing the equations

🧩 The method

  1. Decide what the carbon product is: the question will say CO or carbon (soot).
  2. Carbon: one CO or one C per carbon atom in the fuel.
  3. Hydrogen: unchanged — half the H atoms become H2O, exactly as in complete combustion.
  4. Oxygen last: count the O atoms in the products, remembering CO has one and C has none, then halve.
  5. Double through if you need whole numbers.
WORKED EXAMPLE

Write equations for the incomplete combustion of ethane, C2H6, forming (a) carbon monoxide and (b) soot.

(a) carbon monoxide 2 C → 2CO    6 H → 3H₂O O atoms in products: 2 from CO + 3 from water = 5, so 2½O₂. C₂H₆ + 2½O₂ → 2CO + 3H₂O 2C₂H₆ + 5O₂ → 4CO + 6H₂O (b) soot Now the carbon takes no oxygen at all, so only the water needs any. C₂H₆ + 1½O₂ → 2C + 3H₂O Compare the three oxygen coefficients for ethane: 3½ complete, 2½ to CO, 1½ to soot. Less oxygen, less oxidation.
WORKED EXAMPLE

Calculate the mass of carbon monoxide produced if 1.00 g of methane, CH4, burns with all its carbon converted to CO. (Mr: CH4 = 16.05, CO = 28.01)

Step 1 — moles of methane n = 1.00 ÷ 16.05 = 0.0623 mol Step 2 — ratio from the equation 2CH₄ + 3O₂ → 2CO + 4H₂O, so CH₄ : CO is 1 : 1. n(CO) = 0.0623 mol Step 3 — mass 0.0623 × 28.01 = 1.745 mass of CO = 1.75 g From one gram of gas. In an unventilated room that is a lethal quantity.

Why carbon monoxide is so dangerous

Carbon monoxide is colourless and odourless, so nothing warns you it is there — it takes a detector. Once inhaled it binds to haemoglobin, and it binds far more strongly than oxygen does and effectively irreversibly. Every haemoglobin molecule it occupies is one that can no longer carry oxygen.

The consequences follow from that single fact: the blood’s oxygen-carrying capacity falls, so tissues are starved even though breathing feels normal. Symptoms run from headache and dizziness to loss of consciousness and death. It is a genuine hazard of car engines and faulty boilers, where the oxygen supply is restricted.

Soot causes different problems: it is a particulate, and particulates cause respiratory illness, blacken buildings, and contribute to global dimming.

Which fuels soot the most

Compounds that are richer in carbon have more carbon to dispose of per gram and less hydrogen to help mop up the oxygen, so they are more likely to leave unburnt carbon behind. Aromatic compounds are the classic offenders — benzene burns with a spectacularly smoky flame.

CARBON CONTENT AND SOOTpercentage of carbon by mass52.1%ethanolC₂H₅OH83.6%hexaneC₆H₁₄92.2%benzeneC₆H₆sootier flamethe more carbon per gram, the more soot when oxygen runs short
Percentage of carbon by mass is a quick, quantitative way of ranking fuels for sootiness.
WORKED EXAMPLE

Calculate the percentage of carbon by mass in ethanol (C2H5OH, Mr = 46.08), hexane (C6H14, Mr = 86.20) and benzene (C6H6, Mr = 78.12), and predict which burns with the sootiest flame.

The calculation % C = (total mass of carbon ÷ M r) × 100 Ethanol (2 × 12.01) ÷ 46.08 × 100 = 52.1% Hexane (6 × 12.01) ÷ 86.20 × 100 = 83.6% Benzene (6 × 12.01) ÷ 78.12 × 100 = 92.2% benzene is sootiest, ethanol cleanest Same six carbons in hexane and benzene, but benzene carries eight fewer hydrogens, so a far greater share of its mass is carbon.

💡 Exam tip

⚠️ Common mix-up

Up next: Carbon Dioxide from Burning Fuels — how to work out exactly how much CO2 a fuel produces, and why the answer differs so much from one fuel to another.

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