IB Chemistry SL Topic 5 — The Rate of Reaction Paper 1 & 2 Core idea ~13 min read

Maxwell–Boltzmann Distributions

Every explanation in this sub-topic has leaned on the phrase “a greater proportion of particles with enough energy”. This is the graph that phrase refers to — and once you can read it, those explanations stop being something to memorise.

📚 What you need to know

Reading the curve

THE SPREAD OF PARTICLE ENERGIESEₐEₘₚmost probable energythese can reactKINETIC ENERGYPARTICLESthe curve starts at the origin and never touches the axis again
The tail is what matters. It looks negligible, but the particles in it are the only ones doing any chemistry.

Four features are worth being able to justify rather than just recall:

Note where Ea sits: well to the right of the peak, in the thin part of the tail. That is the visual statement of something from the collision theory page — only a tiny fraction of particles can react at any moment, which is why reactions take time at all.

What temperature does

RAISING THE TEMPERATUREEₐlower Thigher Tfar more particles nowclear the barrierKINETIC ENERGYpeak lower and further right, curves cross once, total area unchanged
The shaded region beyond Ea is roughly twice as large for the hotter sample, even though the curve has barely moved.

Everything about the shape follows from one constraint: the number of particles has not changed, so the area under both curves must be the same. Heating spreads the particles over a wider range of energies, and if the curve gets wider it must also get lower to keep the area constant.

🧩 Sketching two temperatures

  1. Both curves start at the origin.
  2. The hotter curve’s peak is lower and further right.
  3. The two curves cross exactly once.
  4. Beyond the crossing point, the hotter curve’s tail stays above the colder one.
  5. Mark Ea on the energy axis with a vertical line, and shade to the right of it.
Examiners now tend to ask about lowering the temperature rather than raising it, which catches out anyone reciting a memorised answer. Same theory, reversed: the peak becomes higher and moves left, the tail drops, and far fewer particles lie beyond Ea.
WORKED EXAMPLE

Use a Maxwell–Boltzmann distribution to explain why cooling a reaction mixture from 40 °C to 20 °C slows it down considerably.

Step 1 — what happens to the curve At the lower temperature the peak becomes higher and shifts to the LEFT, and the tail falls. Step 2 — the area beyond Eₐ Eₐ stays exactly where it is — cooling does not change the barrier. But the area to the right of it is now much smaller. Step 3 — link to collisions smaller proportion with E ≥ Eₐ → fewer successful collisions per second Step 4 — the secondary effect Particles also move more slowly, so they collide slightly less often. This matters far less than the change in proportion. the rate falls sharply

What a catalyst does

ADDING A CATALYSTEₐ withoutEₐ withthe extra particles thatcan now reactKINETIC ENERGYthe curve does not move — the catalyst moves the barrier instead
Nothing about the particles has changed. The line marking Ea has moved left, and the shaded area grows because of where the line now sits.

This is the crucial contrast with temperature and it is drawn very differently. Temperature redraws the curve and leaves Ea alone. A catalyst leaves the curve exactly where it was and moves Ea. Both end up increasing the shaded area, for completely different reasons.

If a question asks you to shade the particles that can react when a catalyst is present, shade everything to the right of the catalysed Ea — the whole region, not just the extra strip the catalyst gained you. The extra strip is the increase; the total is the answer.
WORKED EXAMPLE

A student sketches two Maxwell–Boltzmann curves for the same sample at two temperatures. Their sketch shows (i) both curves starting a little way up the y-axis, (ii) the two curves crossing twice, and (iii) the hotter curve with a higher peak shifted right. Identify each error.

(i) starting above the origin Wrong — the curve must begin at (0, 0), because no particles have zero kinetic energy. (ii) crossing twice Wrong — two curves for the same number of particles cross exactly ONCE. (iii) higher peak Wrong — shifting right is correct, but the hotter peak must be LOWER, or the area would exceed the number of particles present. only the rightward shift was right Every one of these errors traces back to the same rule: the area under the curve cannot change.
WORKED EXAMPLE

Explain, using the distribution, why a 10 °C rise can roughly double a reaction rate even though the average particle energy rises by only a few percent.

Step 1 — where Eₐ sits Eₐ lies far out in the tail, where the curve is falling away steeply. Step 2 — what a small shift does there A small rightward shift of the whole curve moves a disproportionately large slice of area past Eₐ, because the tail is so steep at that point. Step 3 — the numbers average energy +3%, but the area beyond Eₐ roughly doubles rate roughly doubles The rate follows the AREA BEYOND the barrier, not the average energy. That is the whole reason temperature is such a powerful lever.

💡 Exam tip

⚠️ Common mix-up

That completes How Fast? The Rate of Reaction. You can measure a rate, take it off a graph with a tangent, explain every factor that changes it in terms of collisions, and draw the distribution that underpins the lot. Up next in Topic 5: How Far? — reactions that stop before they finish, and why.

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