IB Physics SL Topic 4 — Force Fields Paper 1 & 2 F = EQ ~8 min read

Charges in Electric Fields

Swap the magnetic field for an electric one and the story changes shape — literally. A magnetic field bends a charge into a circle; an electric field pushes it in one steady direction and curves it into a parabola, exactly like a ball thrown sideways under gravity. This is the trick behind the old cathode-ray tube and every ink-jet printer.

📘 What you need to know

What an Electric Field Does to a Charge

Drop a charge into an electric field and it feels a force straight away. The size of that force is beautifully simple — the field strength times the charge:

Force on a charge in an electric field F = E Q

Here F is the force (N), E is the field strength (N C−1), and Q is the charge (C). A positive charge is pushed along the field lines; a negative charge is pushed the opposite way. If the charge starts at rest, it simply accelerates in a straight line along the field. The interesting case is when it’s already moving across the field.

Moving Across the Field: the Parabola

Picture a charge shot horizontally into the gap between two charged plates. Its forward speed carries on unchanged, but the field adds a steady sideways force the whole time it’s between the plates. Constant forward motion plus a constant sideways pull is the exact recipe for a parabola — the same maths as a ball rolled off a table, only here “gravity” is the electric force.

+++++ E + v F = EQa + charge curves toward the − plate
Blue lines show the field between the plates. The charge keeps its forward speed but feels a constant downward force (red), so it traces a parabola — bending toward the oppositely charged plate.

Which Way Does It Bend?

The direction is just “opposites attract” applied to the plates. Follow the sign of the charge:

positive charge
bends to − plate
negative charge
bends to + plate
no charge (neutron)
straight through

What Controls the Deflection

Two identical plates, two different particles fired in the same way — they won’t bend by the same amount. Three things decide how sharply a particle turns:

+ plate − plate + less deflection more deflection↑ charge q → MORE bend ↑ mass m → LESS bend ↑ speed v → LESS bend same speed → deflection ∝ q ÷ m (a neutral particle: no bend at all)
Same plates, same entry, different particles. A big charge bends more; a big mass or a high speed bends less — so a heavy, fast particle barely curves, while a light, slow, highly charged one swings hard toward the plate.
Quick recap: a charge in an electric field feels a constant force F = EQ, so a charge crossing the field traces a parabola (projectile-style). Positive bends to the − plate, negative to the + plate, neutral goes straight. Deflection grows with charge and shrinks with mass and speed.

🎨 Drawing the path in the exam

  1. Charged? If not (a neutron), draw a straight line — no force, no bend
  2. Which plate? Positive charge curves toward the plate; negative toward the + plate
  3. Shape: start the path horizontal, then let it curve more and more — a parabola, never a circle or a straight diagonal
  4. Compare deflection with q ÷ m (at the same speed): more charge steepens it, more mass or speed flattens it
  5. Match the entry: if two particles enter at the same point and speed, draw both leaving that point together, then separating by their different curvatures
WE 1

A proton is fired horizontally into the uniform field between two parallel plates and follows a curved path toward the negative plate. An alpha particle (charge 2× the proton, mass 4× the proton) is then fired in at the same point with the same speed. Describe how its path compares with the proton’s.

Same direction of bend? The alpha is also positive → it curves toward the same (negative) plate Compare the deflection (same E, same v) deflection ∝ Q ÷ m alpha ÷ proton = (2 ÷ 4) = 0.5 the alpha deflects half as much Twice the charge would bend it more, but four times the mass wins — so the alpha traces a shallower parabola, curving the same way but only half as far.
WE 2

An electron (charge 1.60 × 10⁻¹⁹ C, mass 9.11 × 10⁻³¹ kg) sits in a uniform electric field of strength 3.0 × 10⁴ N C⁻¹. (a) Calculate the electric force on the electron. (b) Calculate its acceleration.

Part (a) — use F = EQ F = 3.0 × 10⁴ × 1.60 × 10⁻¹⁹ F ≈ 4.8 × 10⁻¹⁵ N Part (b) — use F = ma → a = F ÷ m a = 4.8 × 10⁻¹⁵ ÷ 9.11 × 10⁻³¹ a ≈ 5.3 × 10¹⁵ m s⁻² A tiny force, but on such a tiny mass it’s a colossal acceleration — which is why electron beams bend so easily.

💡 Top tips

⚠ Common mistakes

Up next: we switch both fields on at once. Cross an electric field with a magnetic one and their forces can be set to cancel exactly — a “velocity selector” that lets only one speed of particle through in a straight line. That’s the final page of this topic.

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