IB Physics SLTopic 4 — Force FieldsPaper 1 & 2F = BIL sin θ~8 min read
Force on a Current-Carrying Wire
Look inside a loudspeaker or an electric motor and you’ll find the same quiet trick doing all the work: a wire carrying a current, sitting inside a magnetic field, gets pushed. Not a nudge you have to imagine — a real, measurable force you can calculate and point in a direction. This page shows you exactly how big that push is and which way it goes.
📘 What you need to know
A wire carrying a current, placed in a magnetic field, feels a real force — because the current is moving charge, and moving charge and a field can never ignore each other
The size of the push is F = BIL sin θ, where B is flux density (T), I the current (A), L the length of wire in the field (m), and θ the angle between the wire and the field
The force is biggest when the wire is perpendicular to the field (θ = 90°, sin θ = 1), giving simply F = BIL
The force is zero when the wire lies parallel to the field (θ = 0°) — running along the lines, it gets no push at all
Force, field and current are mutually perpendicular — all three point at right angles to one another
The direction of the force comes from Fleming’s left-hand rule: thuMb = Motion/force, First finger = Field, seCond finger = Current (conventional, + → −)
In 3D sketches, a dot (·) means “out of the page” and a cross (×) means “into the page”
Why a Current-Carrying Wire Gets Pushed
On the last page we saw that a current makes its own magnetic field, looping in circles around the wire. Now put that wire inside another magnetic field — say between the poles of a magnet. The wire’s own field and the external field can’t sit politely on top of each other: they combine, bunching up on one side of the wire and thinning out on the other. That lopsided field is what pushes the wire sideways, and we call it the motor effect.
You can watch it in a moment: rest a loose copper rod across two rails inside a magnet’s field and connect it to a battery. The instant current flows, the rod rolls — jumping in the direction of the force. Switch the current off and it stops. That little jump is the same physics that spins every electric motor.
How Big Is the Force? F = BIL sin θ
The strength of the push is set by one tidy equation. It gathers together everything that could reasonably matter — how strong the field is, how much current flows, how much wire is in the field, and how the wire is angled.
Force on a current-carrying wireF = BIL sin θ
Reading it symbol by symbol: F is the force on the wire (N); B is the flux density of the applied field (T); I is the current in the wire (A); L is the length of wire (m); and θ is the angle between the wire and the field. So the force grows if you turn up any of three things — a stronger field, a bigger current, or a longer wire in the field.
One detail examiners love: L is only the length of wire that is actually inside the field. If a 30 cm wire pokes through a magnet’s gap but just 4 cm of it sits between the poles, then L = 0.04 m, not 0.30 m. The rest of the wire is out in the open, feeling nothing.
The Angle Does the Steering
That sin θ on the end is doing something important: it measures how squarely the wire cuts across the field. Line the wire up at right angles to the field and it slices straight through the lines — maximum push. Lay it along the lines instead and it never crosses them — no push at all.
The blue arrows are the applied field; the teal line is the wire. Cutting straight across the field (left) gives the maximum force F = BIL; lying along it (right) gives no force at all. Everything in between follows sin θ.
wire ⟂ field (θ = 90°)
sin θ = 1 →
MAX force F = BIL
wire ∥ field (θ = 0°)
sin θ = 0 →
NO force F = 0
Which Way Does It Push? Fleming’s Left-Hand Rule
Now for the direction. The force, the field and the current are always mutually perpendicular — pick any two and the third sticks out at a right angle to both. To untangle which way is which, we use Fleming’s left-hand rule. Hold out your left hand with the thumb, first finger and second finger all at right angles, and each one names a quantity:
thuMb → Motion (the force F)
First finger → Field (the applied field B, pointing N → S)
seCond finger → Current (the conventional current I, from + to −)
The letters do the remembering for you: M–F–C hides inside thuMb, First, seCond.
Force, field and current sit at right angles to one another. Point your left thumb, first finger and second finger apart and the letters line up: thuMb = Motion, First = Field, seCond = Current. Dots and crosses handle the “into or out of the page” directions.
Those dots and crosses come up constantly, so pin the picture down: think of an arrow in flight. Coming straight at you (out of the page) you’d see only its sharp tip — a dot. Flying away from you (into the page) you’d see only the crossed feathers at its tail — a cross.
🧠Using Fleming’s left-hand rule
Reach for your left hand — the left is for the force on a wire (a motor). The right hand is a different rule for a different job
First finger → Field — point it along B, from N to S (or straight into/out of the page)
Second finger → Current — point it along the conventional current (+ → −), which is opposite to the way the electrons drift
Thumb → Force — with the other two set, your thumb now points the way the wire is pushed
Reverse the current (or the field) and the force flips — reverse both and it stays put
Quick recap: a current-carrying wire in a field feels a force F = BIL sin θ — largest when the wire is perpendicular to the field (F = BIL), zero when parallel. Force, field and current are mutually perpendicular, and Fleming’s left-hand rule (thuMb = force, First = field, seCond = current) points the force the right way.
WE 1
A straight copper wire of length 8.0 cm carries a current of 4.5 A. The whole wire lies in a uniform magnetic field of flux density 120 mT, at an angle of 55° to the field. (a) Calculate the force on the wire. (b) State the force if the wire were turned to lie perpendicular to the field.
Part (a) — known values
B = 120 mT = 0.120 T, I = 4.5 A
L = 8.0 cm = 0.080 m, θ = 55°
Put them into F = BIL sin θF = 0.120 × 4.5 × 0.080 × sin 55°F = 0.0432 × 0.819 = 0.0354 NF ≈ 0.035 NPart (b) — perpendicular (θ = 90°, sin θ = 1)F = BIL = 0.120 × 4.5 × 0.080F ≈ 0.043 N (the maximum)Turning the wire square-on lifts the force from 0.035 N up to its largest possible value, 0.043 N.
WE 2
A straight wire lies horizontally across the page, carrying a conventional current to the right. It sits in a uniform magnetic field pointing out of the page. (a) State the direction of the magnetic force on the wire. (b) State what happens to the force if the current is reversed.
Part (a) — apply Fleming’s left-hand rule
First finger (field) → out of the page (·)
seCond finger (current) → to the right
Thumb (force) then points…
downwards (down the page)Part (b) — reverse the current
Flip the current and, with the field unchanged, the force flips too
upwardsReversing either the current or the field alone reverses the force; reversing both would leave it pointing the same way.
💡 Top tips
L is only the length in the field. If part of the wire sticks out past the poles, that part feels no force — use just the length sitting between them
It’s sin θ, not cos θ. θ is measured between the wire and the field, so perpendicular (90°) gives the biggest force and parallel (0°) gives none — sketch it if you’re unsure
Always use conventional current (+ → −) in Fleming’s left-hand rule. Electron flow points the opposite way and will flip your force
Left hand for this force. The right-hand version is a separate rule for a generator; using it here reverses your answer
âš Common mistakes
Using the wire’s full length when only a short stretch of it lies in the field
Dropping the sin θ, or swapping it for cos θ, when the wire isn’t perpendicular to the field
Feeding electron-flow direction into Fleming’s left-hand rule instead of conventional current — the force comes out backwards
Thinking a wire lined up parallel to the field feels the strongest push — parallel is actually where the force is zero
Up next: we place two current-carrying wires side by side, each one sitting in the magnetic field made by the other — and find out whether they pull together or push apart. That’s the force between parallel conductors, and it builds directly on the F = BIL you’ve just learned.
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