IB Physics SL Tool 3 — Mathematics Paper 1 & 2 & IA Gradient, intercept, area ~9 min read

Graphing Skills

A good graph does something a table never can: it makes a relationship visible. The shape of a line tells you whether two quantities are proportional, the gradient often is a physical quantity, and the area underneath can be another one entirely. Learn to plot cleanly, fit a line fairly, and read a graph properly, and you’ll unlock some of the most reliable marks in the whole course — especially in your Internal Assessment.

📘 What you need to know

Plotting a graph well

Before any physics comes out of a graph, the plotting has to be right. The independent variable — the one you controlled — goes across the bottom; the dependent one goes up the side. Label both axes with units, pick linear scales that spread the data across the grid, and mark each point with a small, sharp cross.

🎨 Plotting checklist

  1. Label both axes with the quantity and its unit
  2. Choose scales that make the points fill more than half the grid
  3. Plot accurately with small crosses, in pencil, so mistakes can be fixed
  4. Draw the line of best fit — straight with a ruler, or a smooth freehand curve

Lines of best fit

A line of best fit shows the underlying trend, ignoring the scatter of individual points. It can be straight or a smooth curve, whichever the data suggests — the key is that points sit balanced on both sides. It’s only drawn through the origin if the data genuinely supports that.

A trap worth naming: “line of best fit” doesn’t mean “straight line”. If the points curve, force a ruler through them and you’ll misrepresent the physics. Let the data choose the shape — and if it’s a curve, draw it smoothly in one confident sweep rather than joining the dots.

Reading the gradient

On a straight-line graph the gradient is constant, and it usually carries real meaning — the gradient of a resistance-against-length graph, for instance, tells you resistance per metre. To find it, draw a large triangle on the line (large triangles shrink the reading error), take the values off the axes, and divide.

Gradient m = Δy ÷ Δx = (y2y1) ÷ (x2x1)
Δx Δy length / m resistance / Ω line of best fit
Draw the gradient triangle as large as the line allows, then read Δy and Δx off the axes.

Intercepts and the equation of a line

Every straight-line graph obeys y = mx + c, where m is the gradient and c is the y-intercept — the value of y where the line crosses the vertical axis at x = 0. Reading off both lets you write the full relationship between the variables.

Straight-line equation y = mx + c

Area under a graph

The region between a line and the x-axis often stands for a physical quantity. The classic case: the area under a velocity–time graph is the displacement. For straight-line graphs you find it by splitting the region into triangles and rectangles; for curves, you count squares or divide it into strips.

½ b h b h time / s velocity / m s⁻¹ area = displacement
Split the area under a straight-line graph into a triangle and a rectangle; their sum is the displacement.

Linearising a curve

Straight lines are far easier to read than curves, so physicists often linearise — rearrange a relationship until plotting the right combination of variables gives a straight line. The pendulum is the perfect example. Its period is T = 2π√(L ÷ g), a curve when you plot T against L. Square both sides and it straightens out.

Linearising the pendulum T² = (4π² ÷ g) L
L T T vs L (curved) square T L T² vs L (straight)
Plotting T² against L turns the curve into a straight line whose gradient is 4π² ÷ g.
Quick recap: plot with labelled axes and sensible scales; fit a balanced line (straight or curved); gradient = Δy ÷ Δx from a large triangle; intercept gives c in y = mx + c; area often means a physical quantity; and linearise curves to analyse them.
WE 1

A best-fit line on a graph of resistance against length passes through the points (0.20 m, 4.0 Ω) and (1.80 m, 28.0 Ω). Find the gradient and state what it represents.

Use two points that lie on the line (not raw data points) and apply the gradient formula.

Gradient m = Δy ÷ Δx = (28.0 − 4.0) ÷ (1.80 − 0.20) = 24.0 ÷ 1.60 = 15 Ω m⁻¹ gradient = 15 Ω m⁻¹ The units (Ω per m) reveal the meaning: this is the resistance per unit length of the wire.
WE 2

A student plots T² against L for a simple pendulum and measures a gradient of 4.0 s² m⁻¹. Given T² = (4π² ÷ g)L, find a value for g.

Compare the graph to y = mx: the gradient equals 4π² ÷ g, so rearrange for g.

Match to y = mx gradient = 4π² ÷ g Rearrange for g g = 4π² ÷ gradient g = (4 × π²) ÷ 4.0 g = 9.9 m s⁻² Reassuringly close to the accepted 9.81 m s⁻² — the linearised graph gives g straight from its gradient.

💡 Top tips

⚠ Common mistakes

Up next: Determining Uncertainties from Graphs — we’ll add error bars to those points and use best and worst-fit lines to put an uncertainty on the gradient and intercept, closing the loop between graphing and uncertainty.

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