IB Physics HL Topic 3 — Oscillations & Waves Paper 1 & 2 Phase angle φ ~12 min read

Phase Angles in Simple Harmonic Motion

Every SHM equation so far assumed the object started tidily — right at the centre or right at the edge. But what if two pendulums are swinging and one is a little ahead of the other? To describe an oscillator that starts partway through its cycle, we add a phase angle. It’s the final tool in the SHM kit: a single number that says “how far into the cycle did this one begin?”

📘 What you need to know

What is a phase angle?

Imagine two identical pendulums with the same frequency and amplitude. You release one, then release the other a moment later. They swing with the same rhythm, but one is always a step behind. That constant “step” between them is the phase difference, and the angle that measures it is the phase angle, φ (phi).

Formally, the phase angle is the difference in angular position compared to an oscillator that starts at equilibrium (x = 0 at t = 0). Since one complete cycle is 2π radians, the phase angle can be anywhere from 0 to 2π.

Phase angle = position around the cycle φ0 π/2 π 3π/2the point’s height gives displacement
Think of one oscillation as a trip round a circle. The phase angle φ is simply where on that circle the object sits at t = 0.

The equations with a phase angle

Adding the phase angle to the SHM equations just shifts the starting point of the curve. The displacement, velocity and acceleration become:

SHM equations with a phase angle x = x0 sin(ωt + φ) v = ωx0 cos(ωt + φ) a = −ω²x0 sin(ωt + φ)

When φ = 0, these collapse back to the familiar “starts at equilibrium” equations — the object begins at x = 0. A non-zero φ simply means it began somewhere else in the cycle.

WE 1

An oscillator is described by x = x₀ sin(ωt + φ) with amplitude x₀ = 0.10 m and phase angle φ = π/6. What is its displacement at t = 0?

Step 1 — at t = 0 the equation gives x = x₀ sin(φ) Step 2 — substitute φ = π/6 (= 30°) x = 0.10 × sin(π/6) = 0.10 × 0.5 x = 0.05 m (5.0 cm) A phase angle of π/6 means the object starts already halfway out — not at the centre.

In phase and out of phase

When two oscillators have a phase difference of zero, they move in perfect step — they’re in phase. Any other phase difference means they’re out of phase. Two special cases come up all the time:

🎯 The phase differences worth memorising

  1. φ = 0 (in phase): the two move together, peaking and crossing zero at the same instants.
  2. φ = π/2 (90°, quarter cycle): one is a quarter of a cycle ahead — like displacement and velocity in SHM.
  3. φ = π (180°, half cycle): perfectly opposite — when one is at its positive peak, the other is at its negative peak.
Two oscillators out of phase by π/2 x t φ = π/2
Same amplitude and period, but the red curve leads the blue by a quarter cycle. The gap between matching features is the phase difference.

Sine and cosine: π/2 apart

This is where phase angles connect back to something you already know. A cosine curve is just a sine curve shifted by a quarter cycle. In other words, sine and cosine are π/2 out of phase:

The sine–cosine phase link x0 cos ωt = x0 sin(ωt + π/2)

That’s exactly why the “starts at amplitude” equations used cosine: starting at the peak is the same as starting at equilibrium but a quarter-cycle ahead. The phase angle is the bridge between the two forms.

Lead and lag: mind the sign

A phase angle can be added or subtracted, and the sign tells you whether the curve shifts left or right — but watch out, because the sign is the opposite of what most people expect:

EquationShiftMeaning
x0 sin(ωtφ)Right (later)The oscillation lags — it happens φ behind
x0 sin(ωt + φ)Left (earlier)The oscillation leads — it happens φ ahead
The sign trap catches almost everyone: a shifts the curve left (the motion happens earlier — it leads), while a −φ shifts it right (later — it lags). It feels backwards, but think of it this way: with +φ, the bracket reaches any given value sooner, so that stage of the motion arrives earlier. Sketch it once and it sticks.

Turning a phase angle into a time delay

A phase difference can be converted into an actual time delay between two oscillators. Since the whole cycle (2π) takes one period T, a phase angle φ corresponds to a time φ/ω:

Phase angle to time delay Δt = φ / ω
WE 2

Two identical pendulums swing with the same period of 1.2 s, but one lags the other by a phase angle of π/2. What is the time delay between them?

Step 1 — find ω ω = 2π/T = 2π/1.2 = 5.24 rad s⁻¹ Step 2 — convert phase to time, Δt = φ/ω Δt = (π/2) / 5.24 = 1.571 / 5.24 Δt = 0.30 s Sense check: π/2 is a quarter of a cycle, and T/4 = 1.2/4 = 0.30 s. Matches.

Phase differences summarised

Phase differenceIn degreesFraction of cycleRelationship
0NoneIn phase (move together)
π/290°Quarter cycleQuarter-cycle apart
π180°Half cycleCompletely opposite (antiphase)
2π360°Full cycleBack in phase

💡 Top tips

⚠ Common mistakes

Quick recap: A phase angle φ says how far into its cycle an oscillator starts, giving x = x0 sin(ωt + φ). Two oscillators are in phase when φ = 0, a quarter-cycle apart at π/2, and opposite at π. Sine and cosine differ by π/2; a +φ leads while −φ lags; and a phase converts to a time delay via Δt = φ/ω.
That completes the whole simple harmonic motion story — from describing an oscillation, through its conditions and equations, to its energy and now phase. Next in this topic, these ideas step up a level: when many oscillators are linked together, the disturbance travels, and we get waves. Head to the next sub-section to see how a single oscillation becomes a wave that carries energy across space.

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