IB Physics HL Topic 3 — Oscillations & Waves Paper 1 & 2 Adding displacements ~11 min read

Superposition

Two people shout across a room and the sound waves pass straight through each other, unharmed. Ripples from two stones cross and carry on. But where they overlap, something happens: the water climbs higher in some places and lies perfectly flat in others. The rule behind it is almost too simple — you just add the displacements. Everything from noise-cancelling headphones to the double-slit experiment falls out of that one sentence.

📘 What you need to know

The principle of superposition

The principle of superposition When two or more waves overlap at a point, the displacement at that point is equal to the sum of the displacements of the individual waves

In symbols, at every single point along the wave:

Adding displacements y = y1 + y2

The crucial word is displacement, not amplitude. Displacement is a vector: a crest counts as positive, a trough as negative. So “adding” two waves can perfectly well mean subtracting, and a big wave plus a big wave can give nothing at all.

Wave 1
y1
add
algebraically
Wave 2
y2
gives
Resultant
y1 + y2
Add the displacements, point by point distance displacement wave 1 wave 2 resultant
At the dotted line the red wave is at +0.87A and the blue at +0.50A, so the purple resultant sits at +1.37A. Do that at every point and you have drawn the resultant wave.
Here’s the trick for sketching a resultant. Don’t try to imagine the whole curve at once. Pick a point. Put your finger on wave 1’s height, then on wave 2’s height, add them (watching the signs), and mark a dot. Do that for the crests, the troughs and the zeros first — those are the easy ones — then join the dots smoothly. Examiners give marks for the dots, not the artistry.

The two extremes

Superposition can give any answer between two limits, and both limits are worth knowing cold.

in phase antiphase crest meets crest crest meets trough add them add them resultant amplitude 2A resultant zero everywhere
Left: identical waves in phase double the amplitude. Right: waves in antiphase cancel exactly, leaving a flat line. Between these extremes you get everything in between.
Two waves of amplitude APhase differenceResultant amplitude
In phase0 (or 360°)2A — maximum
Quarter cycle apart90°1.41A
In antiphase180°0 — complete cancellation

Two pulses meeting

Superposition is easiest to see with two single pulses travelling towards each other. As they overlap, the medium’s displacement is the algebraic sum of the two. Then — and this is the part people find surprising — the pulses carry straight on, completely unchanged. They pass through each other. They do not bounce, merge or lose anything.

two upward pulses one up, one downbefore meeting after twice as tall flat: displacement 0 both pulses continue unchanged
Right column: at the instant of total cancellation the rope is flat everywhere — yet the pulses reappear. The energy is still there, stored in the motion of the rope rather than its displacement.
Where did the energy go? When two pulses cancel completely the displacement is zero, but every particle of the medium is moving fast. The energy is momentarily all kinetic. A moment later the pulses emerge, untouched. Superposition adds displacements, never energies.

✏️ Sketching a resultant wave

  1. Mark the easy points first: where one wave is zero, the resultant equals the other wave.
  2. Where both are crests (or both troughs), add the heights — that’s a maximum of the resultant.
  3. Where a crest meets a trough, subtract. If they’re equal, the resultant is zero there.
  4. Join the dots smoothly. Check the resultant never exceeds A1 + A2.
WE 1

Two waves of the same frequency, with amplitudes 4.0 cm and 3.0 cm, arrive at the same point. Determine the largest and smallest possible amplitude of the resultant wave.

Step 1 — the largest resultant happens when they are in phase Crest lines up with crest, so the displacements add. A = 4.0 + 3.0 = 7.0 cm Step 2 — the smallest happens when they are in antiphase Crest lines up with trough, so one displacement is negative. A = 4.0 − 3.0 = 1.0 cm Between 1.0 cm and 7.0 cm Note it never cancels completely — total cancellation needs equal amplitudes as well as antiphase.
WE 2

At an instant, two overlapping waves have the following displacements at three points. Determine the resultant displacement at each.
P: y1 = +2.0 cm, y2 = −5.0 cm  ·  Q: y1 = +3.0 cm, y2 = +3.0 cm  ·  R: y1 = −4.0 cm, y2 = +4.0 cm

Step 1 — apply y = y₁ + y₂, keeping the signs Step 2 — point P y = (+2.0) + (−5.0) = −3.0 cm Step 3 — point Q y = (+3.0) + (+3.0) = +6.0 cm Step 4 — point R y = (−4.0) + (+4.0) = 0 P: −3.0 cm  |  Q: +6.0 cm  |  R: 0 At R the medium is flat, but only for an instant — and only at that point. Zero displacement is not the same as “no wave”.
WE 3

Two waves of equal amplitude 1.0 unit overlap with a phase difference of 90°. At one point each wave has a displacement of 0.71 units. Determine the resultant displacement there, and state whether this is the maximum possible.

Step 1 — add the displacements at that point y = 0.71 + 0.71 = 1.4 units Step 2 — find the resultant amplitude for a 90° phase difference The two waves are a quarter cycle apart, giving a resultant amplitude of √(1.0² + 1.0²) = √2 = 1.4 units Step 3 — compare 1.4 = 1.4, so this point is the crest of the resultant. y = 1.4 units, and yes — it is the maximum Note 1.4A, not 2A. Only waves exactly in phase reach 2A.

💡 Top tips

⚠ Common mistakes

Quick recap: The principle of superposition says the resultant displacement where waves overlap is the algebraic sum of their individual displacements. In phase gives a maximum (2A for equal waves); in antiphase gives cancellation (zero for equal waves). Displacement is a vector, so keep the signs. Afterwards the waves separate unchanged.
Superposition is the rule. Its consequence has a name: interference. Next we ask where the reinforcing and cancelling happen — and the answer turns out to depend on how much further one wave has travelled than the other. That’s path difference, and with it we can predict bright and dark fringes exactly. On to Interference of Waves.

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