IB Physics HL Topic 3 — Oscillations & Waves Paper 1 & 2 λ ± Δλ ~15 min read

The Doppler Effect

An ambulance screams towards you, passes, and races off. The siren drops in pitch the moment it goes by — you have heard it a hundred times. Here is the strange part: the siren never changed. It sang exactly one note the whole way. What changed was the spacing of the waves arriving at your ear, and it changed because the source was chasing its own sound.

📘 What you need to know

Nobody moving: nothing happens

Start with a source sitting still, pumping out waves at a steady frequency. The wavefronts spread out as perfect circles, evenly spaced in every direction.

Stationary source: wavefronts evenly spaced observer observer λ λ grey dots: the source (centre) and the two observers both observers measure the same wavelength, so both hear the same frequency
No relative motion, no Doppler effect. Left and right are identical.

Move the source, and the circles bunch up

Now let the source move to the right at speed us. Each wavefront still spreads out as a circle from wherever the source was when it emitted it — and by the time it emits the next one, the source has moved forwards.

Moving source: squashed in front, stretched behind observer observerbehind λ + Δλ lower fin front λ − Δλ higher fthe source moves right at speed us each circle is centred where the source was when it emitted that wavefront
Look at the gaps along the line. Ahead of the source they are tight; behind, they are wide. Same waves, same speed — different spacing.
Picture a duck paddling across a pond, sending out ripples. The ripples don’t speed up just because the duck is swimming. The duck simply catches up a little with the ripple it made a moment ago, so the ones in front get packed together. That packing is the Doppler effect. Nothing more mysterious than that.

Why the frequency changes

The wave speed v is set by the medium, not by the source. Air doesn’t care how fast the ambulance is going — sound travels at about 340 m s−1 regardless. So look at the wave equation:

The whole argument in one line v =   with v fixed λ shrinks → f must rise   •   λ grows → f must fall

And the change in wavelength has a name:

Change in wavelength Δλ = change in wavelength (m) bigger Δλ → bigger Doppler shift
Source moves
towards you
wavefronts
bunch up
λ shorter
v = ,
v fixed
f higher
higher pitch
The trap: the source’s own frequency is constant the entire time, and so is the speed of sound. Only the observed frequency changes. Write “the observed frequency increases”, never “the siren’s frequency increases”.

The moment it passes you

Here is something people get wrong. The pitch does not slide smoothly downwards the whole time the ambulance drives past. While it is approaching you hear one steady high note; while it is receding, one steady low note. The drop happens as it goes by.

The frequency you hear as a source passes you observed frequency time f (the source frequency) approaching: steady high pitch receding: steady low pitch it passes you here only at the instant of closest approach do you hear the true source frequency
The famous neeeee-owwww. Two near-constant notes with a rapid slide between them, not one long glide.

It works for light too

Nothing in the argument was about sound. Any wave will do, including light.

Relative motionWavelengthObserved frequencySoundLight
Moving towards observerShorter (λ − Δλ)HigherHigher pitchBlue-shifted
Moving away from observerLonger (λ + Δλ)LowerLower pitchRed-shifted
No relative motionUnchangedUnchangedSame pitchNo shift
Notice the table says relative motion. It genuinely does not matter who is moving. If you run towards a stationary siren, the wavelength sitting in the air is unchanged — but you sweep through more wavefronts every second, so the frequency you receive goes up anyway. Same effect, different bookkeeping.

🚑 Answering any Doppler question

  1. Are they getting closer or further apart? That single question decides everything.
  2. Closer → wavelength shorter, frequency higher (higher pitch, blue-shift).
  3. Further → wavelength longer, frequency lower (lower pitch, red-shift).
  4. Sanity check: the source frequency and the wave speed v never change. If your answer says they did, something has gone wrong.
WE 1

A siren emits sound of frequency 500 Hz. The speed of sound in air is 340 m s⁻¹. An observer measures the wavelength of the sound reaching them as 0.60 m. Determine the wavelength emitted by a stationary siren, the change in wavelength, and the frequency the observer hears. State whether the siren is approaching or receding.

Step 1 — the wavelength if nothing moves λ = v/f = 340/500 λ = 0.68 m Step 2 — the change in wavelength Δλ = 0.68 − 0.60 = 0.08 m Step 3 — the observed frequency, using v = fλ with v unchanged f′ = v/λ′ = 340/0.60 f′ = 567 Hz Step 4 — conclude The wavelength is shortened, so the siren is approaching. Notice v = 340 m s⁻¹ was used twice, unchanged. Only λ and the observed f moved.
WE 2

An ambulance drives along a straight road at constant speed, siren wailing, and passes a pedestrian standing on the pavement. Describe and explain what the pedestrian hears, and state what happens to the frequency emitted by the siren.

While it approaches Wavefronts bunch up in front, so λ is shortened. Since v = fλ with v fixed, the frequency heard is higher than the siren’s — a steady high pitch. As it passes For that instant it is neither approaching nor receding, so the pedestrian hears the true siren frequency. The pitch drops sharply. While it recedes Wavefronts stretch out behind, λ is lengthened, so the frequency heard is lower — a steady low pitch. The siren itself unchanged throughout The siren’s frequency and the speed of sound are both constant. Only the observed frequency changes.
WE 3

A spectral line is measured in a laboratory at 656.3 nm. The same line, in light from a distant galaxy, is observed at 658.9 nm. Determine the change in wavelength, and state and explain whether the galaxy is moving towards or away from Earth.

Step 1 — the change in wavelength Δλ = 658.9 − 656.3 Δλ = 2.6 nm Step 2 — which way has it shifted? The observed wavelength is longer, so the light has moved towards the red end of the spectrum. Step 3 — conclude Red-shifted, so the galaxy is moving away from Earth Longer wavelength means lower frequency means red. Same logic as the ambulance — just with light instead of sound.

💡 Top tips

⚠ Common mistakes

Quick recap: The Doppler effect is the change in observed frequency due to relative motion between source and observer. The wavefronts bunch up in front of a moving source (λ − Δλ, higher f) and stretch out behind it (λ + Δλ, lower f). The source frequency and the wave speed never change. For light, receding sources are red-shifted and approaching sources are blue-shifted.
So far this has all been in words and pictures. But if a star’s spectral line has shifted by 2.6 nm, exactly how fast is it running away from us? There is a beautifully simple equation for that, valid whenever the source is much slower than light. That’s the next page: the Doppler effect of light.

Doppler effect leaving you behind?

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