IB Physics SL Topic 5 — The Atomic & Nuclear World Paper 1 & 2 E = Δmc2 ~8 min read

Mass Defect & Binding Energy

Weigh a nucleus and then weigh its protons and neutrons separately, and something strange happens: the separate parts weigh more than the whole. The missing mass didn’t vanish — it was converted into the energy that binds the nucleus together, following Einstein’s E = mc2. That tiny lost mass is the key to nuclear energy.

📘 What you need to know

The Missing Mass

Take a carbon-12 nucleus. Now imagine pulling out all 6 protons and 6 neutrons and weighing them on their own. Add those masses up and you’ll find the total is bigger than the mass of the intact nucleus. That difference is the mass defect, Δm — the mass “lost” when free nucleons come together to form a bound nucleus.

BOUND NUCLEUS smaller mass< mass SEPARATED NUCLEONS greater massproton neutron
The same nucleons weigh more spread apart than they do bound together. That mass difference is the mass defect — released as binding energy when the nucleus forms, and required to pull it apart again.

Because the separate nucleons are heavier, forming the nucleus releases energy (the extra mass is converted away), and pulling the nucleus back apart requires putting that energy back in. You find the mass defect by adding up the nucleon masses and subtracting the nucleus’s measured mass:

Mass defect Δm = Zmp + (AZ)mnmtotal

Here Z is the proton number, A the nucleon number (so AZ is the neutron count), mp and mn are the proton and neutron masses, and mtotal is the measured mass of the whole nucleus.

Turning Mass into Energy

Einstein’s theory of relativity says mass and energy are two faces of the same thing, linked by the most famous equation in physics. A change in mass corresponds to a change in energy:

Mass–energy equivalence E = Δmc2

So the mass defect isn’t just a curiosity — multiply it by c2 and you get the binding energy, the energy released when the nucleus formed (and the energy you’d need to tear it apart).

separated nucleons
→ bind together, lose Δm →
nucleus + energy released

What Binding Energy Really Means

Be careful with the words here, because examiners test them precisely. Binding energy is defined as the energy needed to completely separate a nucleus into its individual protons and neutrons. It is not energy stored inside the nucleus — it’s energy you have to supply from outside to break the nucleus apart. A bigger binding energy means a more tightly held, more stable nucleus.

The Atomic Mass Unit Shortcut

Nuclear masses are usually quoted in atomic mass units (u), defined as one-twelfth the mass of a carbon-12 atom, where 1 u = 1.661 × 10−27 kg. Rather than converting to kilograms and multiplying by c2 every time, you can use a direct conversion between mass and energy:

Mass–energy conversion 1 u = 931.5 MeV c−2

So a mass defect of, say, 0.03 u is worth about 0.03 × 931.5 ≈ 28 MeV of binding energy — no need to touch kilograms at all.

Quick recap: the nucleus is lighter than its separate parts by the mass defect Δm = Zmp + (A−Z)mn − mtotal; convert it to binding energy with E = Δmc2, or use the shortcut 1 u = 931.5 MeV c−2; binding energy is the energy needed to pull the nucleus fully apart.

🧭 Finding a binding energy

  1. Count the nucleons: protons = Z, neutrons = A − Z
  2. Add up the separate masses: Zmp + (A−Z)mn
  3. Subtract the nucleus’s measured mass to get the mass defect Δm (in u)
  4. Convert to energy: either × 1.661×10−27 then × c2, or simply × 931.5 to get MeV
  5. For binding energy per nucleon, divide the total binding energy by A
WE 1

The binding energy per nucleon of carbon-12 is 7.68 MeV. Calculate the total energy needed to completely separate a carbon-12 nucleus into its individual nucleons.

Step 1 — count the nucleons carbon-12 has 6 protons + 6 neutrons = 12 nucleons Step 2 — total binding energy = per-nucleon × A total = 7.68 × 12 total = 92.16 MeV ≈ 92.2 MeV This is the energy you’d have to put in to pull the nucleus completely apart.
WE 2

A helium-4 nucleus has a measured mass of 4.001506 u. Using mp = 1.007276 u and mn = 1.008665 u, calculate (a) the mass defect, and (b) the binding energy per nucleon in MeV.

Part (a) — mass defect He-4 has Z = 2, so 2 protons and 2 neutrons Δm = (2 × 1.007276) + (2 × 1.008665) − 4.001506 Δm = 4.031882 − 4.001506 = 0.030376 u Δm ≈ 0.0304 u Part (b) — binding energy per nucleon total BE = 0.030376 × 931.5 total BE ≈ 28.3 MeV per nucleon = 28.3 ÷ 4 ≈ 7.1 MeV per nucleon Helium-4 is unusually stable, which is why its binding energy per nucleon is so high.

💡 Top tips

⚠ Common mistakes

Up next: Binding Energy per Nucleon Curve. Now you can calculate binding energy per nucleon — next we plot it against nucleon number to see why iron is the most stable element, and where fusion and fission each release energy.

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