IB Physics SL Topic B.2 — Climate & the Greenhouse Effect Paper 1 & 2 Solar Constant · Radiative Intensity ~6 min read

The Solar Constant

Every calculation about Earth’s climate starts with the same question: how much energy from the Sun actually reaches us? The solar constant answers that — and a bit of sphere geometry explains why the planet as a whole only “sees” a quarter of it on average.

📘 What you need to know

Defining the Solar Constant

Think of the Sun as a source radiating power equally in every direction. By the time that energy has travelled out to Earth’s orbit, it has spread across the surface of an enormous imaginary sphere with radius equal to the Sun–Earth distance. The solar constant is simply the power passing through one square metre of that sphere’s surface.

Solar constant S = P ÷ (4πr2)

where P is the Sun’s total power output (W) and r is the mean Sun–Earth distance (m). It’s worth being precise in an exam: the solar constant is defined above the atmosphere, not at ground level — plenty of that energy gets absorbed or scattered before it ever reaches the surface.

imaginary sphere, surface area = 4πr2 r mean Sun–Earth distance SUN power output P EARTH Why S ÷ 4? disc πrp2 sphere 4πrp2 mean intensity = S⁄4
Radiation from the Sun spreads evenly across an imaginary sphere of radius r. Earth intercepts only a small disc of that sphere — which is why its whole-surface average intensity works out to S⁄4.

Why the Solar Constant Isn’t Perfectly Constant

Calculations of the solar constant always assume the radiation lands on a plane perpendicular to the beam and that Earth sits at its mean orbital distance — that’s what keeps S a single, quotable figure rather than a constantly shifting one.

From a Point Source to a Whole Planet

A planet’s radius rp gives it a spherical surface area of 4πrp2, but from the Sun’s point of view, the planet only ever presents its cross-sectional disc, πrp2, to the incoming beam. Spreading the intercepted power back out over the whole sphere gives the mean radiative intensity:

Mean radiative intensity over a planet S × (πrp2 ÷ 4πrp2) = S ÷ 4

This S⁄4 figure is what you plug into an energy-balance model as the average incoming intensity over Earth’s whole surface — day side, night side, poles and equator all averaged together.

Quick recap: S = P ÷ 4πr² is the intensity at the top of the atmosphere facing the Sun directly. Averaged over the whole planet’s surface, that becomes S⁄4.
WE 1

A star radiates energy at a rate of 5.0 × 10²⁶ W. A planet orbits at a mean distance of 2.0 × 10¹¹ m from the star. Calculate the solar constant experienced by the planet.

Step 1 — Write the equation S = P ÷ (4πr2) Step 2 — Substitute values S = (5.0 × 10²⁶) ÷ [4π × (2.0 × 10¹¹)²] S = (5.0 × 10²⁶) ÷ (5.03 × 10²³) S ≈ 990 W m⁻² Notably lower than Earth’s 1360 W m⁻² — this planet orbits further out relative to its star’s output.
WE 2

Using S = 1360 W m⁻² for Earth, calculate the mean radiative intensity averaged over Earth’s entire surface.

Step 1 — Recall the relationship mean intensity = S ÷ 4 Step 2 — Substitute mean intensity = 1360 ÷ 4 = 340 W m⁻² This is the figure energy-balance models use as Earth’s average incoming intensity, before albedo removes a further slice of it.

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⚠ Common mistakes

Up next: Greenhouse Gases — where we look at exactly which gases in the atmosphere absorb Earth’s outgoing radiation, and why some matter far more to the greenhouse effect than others.

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