IB Maths AA SL Paper 1 & 2 15 min read

Reciprocal & Rational Functions

A reciprocal function is f(x) = 1x — the simplest function with asymptotes. A linear rational function is its bigger sibling, f(x) = ax + bcx + d. Both behave the same way — every key feature comes from the four constants.

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What you need to know

  • The reciprocal function y = 1x has asymptotes x = 0 and y = 0, no intercepts, and is self-inverse
  • A linear rational function y = ax + bcx + d has the same overall shape
  • Vertical asymptote at x = −dc (where the denominator is zero)
  • Horizontal asymptote at y = ac (the limiting value as |x| → ∞)
  • y-intercept at y = bd; x-intercept (root) at x = −ba
  • Sketches must label intercept coordinates and asymptote equations

The Reciprocal Function

The reciprocal function is defined as:

f(x) = 1x,   x ≠ 0

Its domain is all real numbers except 0 (you can’t divide by zero), and its range is also all real numbers except 0 (the curve never actually equals zero). It’s a self-inverse function: applying it twice gets you back to where you started.

The Graph of y = 1/x
x y O y = 0 x = 0 x, y > 0 x, y < 0

Key features of y = 1x

Why asymptotes? As x gets close to 0, 1x blows up to ±∞ — that’s the vertical asymptote. As x gets very large, 1x shrinks to 0 — that’s the horizontal asymptote.

Linear Rational Functions

A linear rational function generalises the reciprocal — it’s a fraction with linear top and bottom:

f(x) = ax + bcx + d,   x ≠ −dc

The reciprocal function 1x is just the special case where a = 0, b = 1, c = 1, d = 0. The four constants a, b, c, d tell you everything about the graph:

Reading the Constants
f(x) = ax + bcx + d
Horizontal Asymptote
y = ac

The limiting value of y as |x| → ∞.

Vertical Asymptote
x = −dc

The value that makes the denominator zero.

y-Intercept
(0, bd)

Substitute x = 0. Doesn’t exist if d = 0.

x-Intercept (root)
(−ba, 0)

Set the numerator = 0. Doesn’t exist if a = 0.

Anatomy of a Rational Graph

Here’s what a typical rational graph looks like — using f(x) = 10 − 5xx + 2 as an example (vertical asymptote at x = −2, horizontal at y = −5):

Linear Rational Graph — All Features Marked
x y O (0, 5) (2, 0) y = −5 x = −2

The shape never changes. Every rational function looks like this — two branches separated by a vertical asymptote, both approaching a horizontal asymptote. Once you’ve located the four key features, the sketch is straightforward.

Domain and Range

For f(x) = ax + bcx + d:

Sketching Strategy

  1. Find the vertical asymptote — set the denominator to zero and solve.
  2. Find the horizontal asymptote — read off y = ac from the leading coefficients.
  3. Find the y-intercept — substitute x = 0.
  4. Find the x-intercept — set the numerator to zero and solve.
  5. Draw the asymptotes as dashed lines.
  6. Sketch the two branches through the intercepts, approaching the asymptotes but never crossing them.
  7. Label everything — coordinates of intercepts and equations of asymptotes.

Worked Examples

Example 1 — Reciprocal graph features

For f(x) = 1x, state: (a) the domain, (b) the range, (c) the equations of both asymptotes.

Answer:

(a) Domain: x can be any real number except 0 (denominator). x ∈ ℝ, x ≠ 0 (b) Range: 1/x is never 0 (no value of x gives output 0). f(x) ∈ ℝ, f(x) ≠ 0 (c) Asymptotes: where the function blows up or levels off. x = 0 and y = 0

Example 2 — Find all features of a rational function

For f(x) = 3x + 6x − 2, find: (a) the asymptotes, (b) the intercepts.

Answer:

Identify a = 3, b = 6, c = 1, d = −2. (a) Vertical asymptote: denominator = 0. x − 2 = 0 → x = 2 Horizontal asymptote: y = a/c. y = 3/1 = 3 x = 2 and y = 3 (b) y-intercept: substitute x = 0. f(0) = (0 + 6)/(0 − 2) = 6/(−2) = −3 y-intercept: (0, −3) x-intercept: set numerator = 0. 3x + 6 = 0 → x = −2 x-intercept: (−2, 0)

Example 3 — Full problem with sketch (asymptotes, intercepts, sketch)

The function f is defined by f(x) = 10 − 5xx + 2 for x ≠ −2.

(a) Write down the equations of the vertical and horizontal asymptotes.

Vertical: denominator = 0. x + 2 = 0 x = −2 Horizontal: limiting value as |x| → ∞. As x gets large, (10 − 5x)/(x + 2) ≈ −5x/x = −5 y = −5 Or just read off a/c = −5/1 = −5 (since a = −5, c = 1).

(b) Find the coordinates of the intercepts with the axes.

y-intercept: substitute x = 0. f(0) = (10 − 0)/(0 + 2) = 10/2 = 5 y-intercept: (0, 5) x-intercept: set numerator = 0. 10 − 5x = 0 → x = 2 x-intercept: (2, 0)

(c) Sketch the graph of f, labelling all key features.

Draw the asymptotes x = −2 and y = −5 as dashed lines. Plot the intercepts (0, 5) and (2, 0). Sketch two branches: Right branch (x > −2): passes through (0, 5) and (2, 0), approaches y = −5 from above as x → ∞. Left branch (x < −2): approaches y = −5 from below as x → −∞, dives to −∞ as x → −2 from the left. Always include both intercepts AND both asymptote equations on the sketch.

Example 4 — Domain and range

For f(x) = 2x + 1x − 4, write down the domain and range.

Answer:

Domain: all real numbers except where the denominator is zero. x − 4 ≠ 0 → x ≠ 4 x ∈ ℝ, x ≠ 4 Range: all real numbers except the horizontal asymptote y = a/c. y = 2/1 = 2 f(x) ∈ ℝ, f(x) ≠ 2 A linear rational function never reaches its horizontal asymptote.

Example 5 — Find the equation given features

A rational function has a vertical asymptote at x = 3, a horizontal asymptote at y = 2, and passes through the origin. Find an equation for f(x).

Answer:

Step 1: write the general form. f(x) = (ax + b) / (cx + d) Step 2: vertical asymptote at x = 3 means −d/c = 3. Pick c = 1, then d = −3 → denominator: x − 3 Step 3: horizontal asymptote at y = 2 means a/c = 2. a/1 = 2 → a = 2 Step 4: passes through origin (0, 0) → b/d = 0, so b = 0. f(x) = 2x / (x − 3) Check: f(0) = 0/(−3) = 0 ✓
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Tips

  • Always identify a, b, c, d first. Once you have all four, every key feature falls out from a simple ratio.
  • For a sketch, label everything: coordinates of both intercepts AND equations of both asymptotes. Missing labels = lost marks.
  • Use your GDC on Paper 2 to verify the shape, but be aware: most GDCs don’t draw the asymptotes. Add them yourself by reading the equation.
  • Asymptote shortcut: for ax + bcx + d, the horizontal asymptote is just the ratio of the leading coefficients a/c.
  • Check the y-intercept by substituting x = 0 — fastest way to verify the equation matches a sketch.

Common mistakes

  • Sign error in the vertical asymptote. x = −dc has a minus sign — for x + 2, the asymptote is x = −2, not +2.
  • Forgetting to label the asymptotes on a sketch. Both vertical AND horizontal asymptote equations must be shown.
  • Drawing branches that cross the asymptotes. Asymptotes are barriers — the curve approaches but never touches them.
  • Using a/c for the y-intercept. The y-intercept is at b/d (set x = 0); a/c is the horizontal asymptote.
  • Including the asymptote in the range. The range excludes a/c — write f(x) ≠ a/c.
  • Believing your GDC’s sketch literally. GDCs often draw a connecting line through the vertical asymptote — that line isn’t real. Manually break the curve at the asymptote.

Final word: Identify a, b, c, d. Compute the four key features. Sketch with everything labelled. The shape is always the same — your job is just to place it correctly on the axes.

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