IB Maths AA SL Topic 3 β€” Geometry & Trig Paper 1 & 2 ~10 min read

Sine Rule, Cosine Rule & Area of a Triangle

When a triangle isn’t right-angled, SOH CAH TOA stops working. You need three new tools instead β€” the sine rule, the cosine rule, and the trig area formula. The hard part isn’t the formulas (they’re all in the booklet); it’s picking the right one.

πŸ“˜ What you need to know

The naming convention (read this first)

Every triangle problem in this note uses the same labelling: capital opposite lowercase. Side a sits opposite angle A; side b sits opposite angle B; side c sits opposite angle C. Get this wrong and every formula falls apart.

Standard triangle labelling
A B C c b a side b is opposite vertex B
Quick rule: if the question gives you a side, look across to the angle directly opposite β€” that’s the matching pair (a ↔ A, etc.). This pairing is what the sine rule and cosine rule are built around.

When to use each formula β€” the decision tree

Look at what the question gives you. The pattern of givens tells you which formula to reach for.

πŸ“ Sine rule (find side)
Given: 2 angles + any 1 side (AAS or ASA).
asin A = bsin B
πŸ“ Sine rule (find angle)
Given: 2 sides + 1 angle opposite one of them.
sin Aa = sin Bb
πŸ“ Cosine rule (find side)
Given: 2 sides + the angle between them (SAS).
a2 = b2+c2βˆ’2bc cos A
πŸ“ Cosine rule (find angle)
Given: all 3 sides (SSS).
cos A = b2+c2βˆ’a22bc
πŸ“¦ Area formula
Given: 2 sides + the angle between them.
A = 12ab sin C
πŸ“ Right-angled triangle?
If the triangle has a right angle, use Pythagoras / SOH CAH TOA β€” they’re faster.
a2+b2=c2
The fastest way to choose: count the pieces of information you’ve got. Two angles + a side β†’ sine rule. Two sides + the included angle β†’ cosine rule (or area). Three sides β†’ cosine rule (rearranged). Side and its opposite angle, plus another side or angle β†’ sine rule.

The sine rule

The sine rule connects each side to the sine of its opposite angle. It says all three of these ratios are equal:

Sine Rule asin A = bsin B = csin C βœ“ in formula booklet

You only ever use two of the three ratios at a time β€” the one with the unknown, and one with full information.

Flip it for angles: when finding an angle, flip the formula upside down: sin Aa = sin Bb. Same rule, easier to rearrange when the unknown is in the numerator.

⚠ The ambiguous case

If you’re given two sides and an angle that’s not between them (an “SSA” setup), the sine rule can sometimes give two valid answers β€” one acute, one obtuse. If sin ΞΈ = 0.6, then ΞΈ could be 36.87Β° or 180Β° βˆ’ 36.87Β° = 143.13Β°. Always check whether the obtuse answer fits the triangle (the angles must add to 180Β°).

The cosine rule

When the sine rule doesn’t apply (because you don’t have an angle paired with its opposite side), you reach for the cosine rule. There are two forms β€” one for finding a side, one for finding an angle:

Cosine Rule (find a side) a2 = b2 + c2 βˆ’ 2bc cos A βœ“ in formula booklet
Cosine Rule (find an angle) cos A = b2 + c2 βˆ’ a22bc βœ“ in formula booklet

πŸ€” The cosine rule is just Pythagoras with a correction

When A = 90Β°, cos A = 0, so the formula becomes a2 = b2 + c2 β€” that’s Pythagoras! The “βˆ’2bc cos A” term is the correction for non-right-angled triangles. The cosine rule is the generalisation; Pythagoras is the special case.

🧠 Memory hook for the cosine rule

The angle A in the formula is always opposite the side you’re finding or matching. So if you want side a, use angle A. If you’re given all three sides and want an angle, the formula matches up: solving for cos A uses a2 as the “subtracted” term in the numerator.

Area of a triangle

Most students know one area formula: half base times height. But that requires you to know the perpendicular height β€” which you usually don’t. The trig version is much more useful in IB:

Area of a Triangle (trig version) Area = 12ab sin C βœ“ in formula booklet
The angle must be the one between the two sides. If you use sides a and b, then angle C (the angle between them) is the right one. Don’t grab a different angle by mistake.

You can also write this as Area = Β½ac sin B or Β½bc sin A β€” same formula, different pairing. Always: two sides Γ— sin(included angle), all halved.

Quick reference β€” what to use when

Find
Given
Use
A side
2 angles + 1 side
sine rule
A side
2 sides + included angle
cosine rule
An angle
2 sides + 1 opposite angle
sine rule (flipped)
An angle
3 sides (SSS)
cosine rule (rearranged)
Area
2 sides + included angle
Β½ab sin C
Anything
right-angled triangle
SOH CAH TOA / Pythagoras

Worked examples

WE 1

Sine rule β€” find a side

In triangle ABC, angle A = 50Β°, angle B = 70Β°, and side a = 8 cm. Find side b.

Step 1: Pick the right pairs Have a ↔ A (full pair), want b with B. Step 2: Set up sine rule bsin 70Β° = 8sin 50Β° Step 3: Solve for b b = 8 Γ— sin 70Β°sin 50Β° = 8 Γ— 0.9397…0.7660… b β‰ˆ 9.81 cm (3 s.f.) cross-multiply if rearranging confuses you!
WE 2

Sine rule β€” find an angle

In triangle ABC, side a = 12, side b = 15, and angle A = 40Β°. Find angle B.

Step 1: Use the flipped form sin B15 = sin 40Β°12 Step 2: Solve for sin B sin B = 15 Γ— sin 40Β°12 = 15 Γ— 0.6428…12 = 0.8035… Step 3: Apply inverse sine B = sin⁻¹(0.8035…) B β‰ˆ 53.5Β° (3 s.f.) check: 180 βˆ’ 53.5 = 126.5Β° also works for sin, but 40+126.5 > 180 so it’s invalid here
WE 3

Cosine rule β€” find a side (SAS)

In triangle ABC, side b = 9, side c = 11, and angle A = 65Β°. Find side a.

Step 1: Apply the cosine rule a2 = b2 + c2 βˆ’ 2bc cos A Step 2: Substitute a2 = 92 + 112 βˆ’ 2(9)(11) cos 65Β° = 81 + 121 βˆ’ 198 Γ— 0.4226… = 202 βˆ’ 83.68… = 118.32… Step 3: Square root a = √118.32… a β‰ˆ 10.9 cm (3 s.f.) don’t forget the square root at the end!
WE 4

Cosine rule β€” find an angle (SSS)

A triangle has sides a = 7, b = 8, c = 13. Find angle C.

Step 1: Use the rearranged cosine rule cos C = a2+b2βˆ’c22ab Step 2: Substitute cos C = 49 + 64 βˆ’ 1692(7)(8) = βˆ’56112 = βˆ’0.5 Step 3: Apply inverse cosine C = cos⁻¹(βˆ’0.5) C = 120Β° negative cosine β†’ obtuse angle. cos⁻¹ handles this automatically.
WE 5

Area using the trig formula

A triangle has two sides of length 6 cm and 9 cm with an included angle of 75Β°. Find its area to 3 s.f.

Step 1: Apply the area formula Area = 12ab sin C Step 2: Substitute a = 6, b = 9, C = 75Β° Area = 12(6)(9) sin 75Β° = 27 Γ— 0.9659… Area β‰ˆ 26.1 cm2 (3 s.f.) always check the angle is the one BETWEEN the two sides!

πŸ’‘ Top tips

⚠ Common mistakes

These three formulas β€” sine rule, cosine rule, and area β€” handle every non-right-angled triangle problem you’ll meet. Combined with Pythagoras and SOH CAH TOA, you’ve now got the full toolkit for any triangle in the IB syllabus.

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